Question

Angle of intersection of two curves y2=4ax x2=4by

Answer 1

equation for Curves

y^2 = 4ax                   Eqn 1

x^2 = 4by                    Eqn 2

Differentiating eqn 1 and 2

2y dy/dx = 4a

and 

2x = 4b dy/dx
dy/dx = 2x/ 4b

Thus

2y * 2x/4b = 4a
 4xy = 16 ab
   xy = 4 ab
Differentiating

xdy/dx + y = 0
  x tan theta = y
theta = taninverse(y/x)

Answer 2

Answer:

angle between two curves

y2=4(X+1)

and

X2=4(y+1)