Question

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism. The angle of prism is -(cos41 degree =0.75)

Answer 1

Here refractive index is sin{(A+Dm)/2}/sin(A/2)=1.5.And ad per the question A=Dm=>sinA/sinA/2=1.5

=>2cos(A/2)=1.5=>cos(A/2)=3/4= 0.7.so 5A =2cos-1(0.75)=41.409° or 41°24′32.4″.