Question

Angle of repose for a rough inclined plane is 60 degree what is the cofficient of if friction ​

Answer 1

Answer:

$\boxed{\mathfrak{Coefficient \ of \ friction \ (\mu) = \sqrt{3}}}$

Given:

Angle of repose (α) = 60°

Explanation:

Angle of repose (α) is the maximum angle of inclination of a rough inclined plane with horizontal such that the block kept on it remains at rest.

At angle of repose,

$\boxed{ \bold{tan \: \alpha = \mu}}$

$\rm \mu \longrightarrow Coefficient \ of \ friction$

By substituting value we get:

$\rm \implies \mu = tan \: 60 \degree \\ \\ \rm \implies \mu = \sqrt{3}$