Question

Angle opposite to equal sides of an isosceles triangle are equal .

Answer 1

Hey mate !!!!!

Here's your answer »»»»»»»»»»

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Let ∆ABD & ∆ACD be two isosceles triangles, where side AB = side AC & AD is perpendicular to BC

AB = AC (given)
AD = AD (common)
angle BDA = angle CDA (90°)

Therefore, ∆ABD is congruent to ∆ACD by RHS congruence condition.

By CPCT, we can say that angle ABD = angle ACD (opposite sides of an isosceles triangle)

Hence proved.

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Hope this helps
@PoojaBBSR

Answer 2

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