Question

Angle P of a triangle is 1/3 of angle R and angle Q is less than angle R by 1/3 rd of it. Find the angles of the triangle.

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Answer 1

r+p+q=180°

But we are given

r+r/3+r-r/3=180°

If we take LCM, we get

(3r+r+3r-r)/3=180°

6r=540°

r=90°

p=90/3=30°

q=90-90/3=60°

So the angles p,q,r are 30°,60°, and 90° respectively.