Angle P of a triangle is 1 by 3 of angle R and angle Q is less than angle R by 1 by 3 of it find the angles of the triangle
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Answer:
let <R =x
so <P =1/3 of x =x/3
and < Q =x-x/3
as we know sum of all angles of triangle = 180
x+ x/3 +x-x/3 = 2x = 180
2x = 180
x = 90
therefore <R = 90
<P=90/3 =30
<Q=90- 90/3= 60
Step-by-step explanation:
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