Angle POS+QOS+QOR=302 FIND THE FOUR ANGLE
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let the 2 bigger angles be x
and smaller one be y
so
we know that it is sum of all angles is 360
we know that opposite sides are same as they are vertically opposite angles
2x+2y=360
x+y=180
and it is given that 2x +y=302
eliminating both equations we get
y = 58°
and x will be ( putting values in above any equation )
x= 122°
and smaller one be y
so
we know that it is sum of all angles is 360
we know that opposite sides are same as they are vertically opposite angles
2x+2y=360
x+y=180
and it is given that 2x +y=302
eliminating both equations we get
y = 58°
and x will be ( putting values in above any equation )
x= 122°
iitaim1:
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pos+qos+qor=302° . pos+qos+qor+rop=360°.we know pos+qos+qor=360°.now 302°+rop=360°and rop=360-302=58°
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