Question

angle poy=40find angle oyp and oyt​

Answer 1

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ANSWER:---------------

PY=PT so PO is the angle bisector of ∠ RPT

note[∴ ][∠OPX= 20°]

∠ORX=∠OTP=90°

(Radius and tangent are perpendicular to each other)

In triangle ORP,

90°+20°+∠POR=180° (Angle Sum Property)

∠POR=70°

∠ROP=∠POT

(Equal tangents subtend equal angles at the centre)

Similarly,

∠ROB=∠BOS and ∠TOA=∠AOS

[note[∴ ][∠ROB + ∠BOS + ∠AOS +

∠TOP = 70° + 70° = 140°

2∠OYP+ 2∠AOS = 140°

∠POR + ∠PTY = 70°

[note][∴ ]∠OYT = 70°]

hope it helps:--

T!—!ANKS!!!!