Angle PQR and QOR forms a linear pair , if a-b=80 .Find the value of a & b.
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Answered by
81
When angles make linear pair their sum becomes 180
So,
A+b=180
=>a=180-b (equation i)
Now,
A-b=80 as given
=>a=80+b (equation ii)
When we compare i and ii, we find out LHS of both the equations are same. Therefore the RHS have to b same or equal.
So, comparing or equating equation i and ii,
180-b=80+b
=>180-80=b+b (moving the constant and variables on separate or opposite side)
=>100=2b
=>100/2=b
=>b=50
Now putting the value of b in either equation i or ii we will get the value of a
So,
A=80+b
=>a=80+50
=>a=130
Hence, a=130 and b=50
So,
A+b=180
=>a=180-b (equation i)
Now,
A-b=80 as given
=>a=80+b (equation ii)
When we compare i and ii, we find out LHS of both the equations are same. Therefore the RHS have to b same or equal.
So, comparing or equating equation i and ii,
180-b=80+b
=>180-80=b+b (moving the constant and variables on separate or opposite side)
=>100=2b
=>100/2=b
=>b=50
Now putting the value of b in either equation i or ii we will get the value of a
So,
A=80+b
=>a=80+50
=>a=130
Hence, a=130 and b=50
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26
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