Angle PQR =angle PRQ then show that angle PQS = PRT .
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∠PQR = ∠PRQ
To prove:∠PQS = ∠PRT
Proof:
∠PQR +∠PQS =180° (by Linear Pair axiom)
∠PQS =180°– ∠PQR — (i)
∠PRQ +∠PRT = 180° (by Linear Pair axiom)
∠PRT = 180° – ∠PRQ
∠PRQ=180°– ∠PQR — (ii) [∠PQR = ∠PRQ]
From (i) and (ii)
∠PQS = ∠PRT = 180°– ∠PQR
∠PQS = ∠PRT Hence, ∠PQS = ∠PRT
#SingodiyaBoy..
To prove:∠PQS = ∠PRT
Proof:
∠PQR +∠PQS =180° (by Linear Pair axiom)
∠PQS =180°– ∠PQR — (i)
∠PRQ +∠PRT = 180° (by Linear Pair axiom)
∠PRT = 180° – ∠PRQ
∠PRQ=180°– ∠PQR — (ii) [∠PQR = ∠PRQ]
From (i) and (ii)
∠PQS = ∠PRT = 180°– ∠PQR
∠PQS = ∠PRT Hence, ∠PQS = ∠PRT
#SingodiyaBoy..
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Answered by
4
☺ Hello mate__ ❤
◾◾here is your answer...
Given: ∠PQR=∠PRQ
To prove: ∠PQS=∠PRT
Proof:
∠PQS+∠PQR=180° (Linear pair) .......eq(1)
∠PRT+∠PRQ=180° (Linear pair) ......eq (2)
From (1) and (2),we can say that
∠PQS+∠PQR=∠PRT+∠PRQ
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
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