Angle QPR = Angle PQR and M and N are points respectively I on sides QR and PR of ΔPQR such that QM = PN. Prove that OP = OQ, where O is the point of intersection of PM and QN.
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In figure, ∠QPR = ∠PQR and M and N are respectively points on sides QR and PR of ∆PQR, such that QM = PN. ... Given: ∠QPR = ∠PQR and M and N are respectively points on side QR and PR of ∆PQR, such that QM = PN. To Prove: OP = OQ, where O is the point of intersection of PM and QN.
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Given: ∠QPR = ∠PQR and M and N are respectively points on side QR and PR of ∆PQR, such that QM = PN. To Prove: OP = OQ, where O is the point of intersection of PM and QN. ∆ABC is an isosceles triangle in which AB = AC. ... Side BA is produced to D such that AD = AB.
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