Question

Angle that the vector A = 2i + 2) makes with y-axis is (a) tan-'(3/2) (b) tạn' (2/3) (c) sin' (2/3) (d) cos' (3/2)​

Answer 1

Explanation:

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Answer 2

Answer:

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Explanation:

A =2

i^+3 j^A .

j^ = 13

cosθ3= 13

cosθ

θ=cos −1 ( 133 )

Using formula, tan(cos −1 x)= x1−x 2

we will get:θ=tan −1 13 31− 139 θ=tan −1 ( 13 )

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