Question

Angle which is 30 degree less than its complement


Factorise

√2x²+7x+5 √2

And the given question in attachment

Answer 1

$\sqrt{2} x {}^{2} + 7x + 5 \sqrt{2} \\ = > \sqrt{2} x {}^{2} + x(2 + 5) + 5 \sqrt{2} = 0 \\ = > \sqrt{2} x {}^{2} + 2x + 5x + 5 \sqrt{2} = 0\\ = \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ = > ( \sqrt{2 } x + 5)(x + \sqrt{2} ) = 0 \\ = > \sqrt{2} x + 5 = 0 \\ = > \sqrt{2} x = - 5 \\ = > x = - \frac{5}{ \sqrt{2} } \\ or \\ = > x + \sqrt{2} = 0 \\ = > x = - \sqrt{2}$

I hope that helps you