angle XLM= (2x - 10)° and angle LMQ= x + 30°, find x.
please explain step by step.
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We have ∠XLM=(2x−10)° and ∠LMQ=(x+30)°
Also, line XY || line PQ
∴ ∠XLM and ∠LMQ are alternate angles.
and alternate angles on parallel lines are congruent.
∴∠XLM=∠LMQ
∴2x−10=x+30
⇒2x−x=30+10
∴x=40°
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