angleA = x +30°, angleB = 3x -30° and angleC = 4x - 60°.
Answers
Answered by
2
Answer:
To show: △ABC is equilateral Property of equilateral triangle
∠A=∠B=∠C=60
Given : ∠A=x+30=60
x=30−−−−−(1)
∠B=3x−30=60
3x=90
x=30−−−−−−−(2)
∠C=x−60=60
4x=120
x=30−−−−−−−−−(3)
From eq (1), (2), (3) x=30
and ∠A=∠B=∠C=60
Hence , △ABC= equilateral
Answered by
0
Answer:
60°
Step-by-step explanation:
According to angles property
Angle a + angle B + angle C = 180°
x+30+3x-30+4x-60=180°
x-60+3x+4x=180
x-60+3x+4x=180
8x-60=180°
8x=180+60
8x=240°
x=8/240
x=30°
Angle A=30 + 30 = 60°
Angle B=3×30-30= 60°
Angle C=4×-60=60°
hence, it is a equilateral triangle
Similar questions