Angles A,B,C of a Triangle ABC satisfy B - A=30° and C- B=45°. Find all the angles.
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If, Angles A,B,C of ∆ABC
so, A+B+C = 180°
it is given that, (B-A)=30°
and, (C-A) = 45°
now,
(A+B+C) - (B-A) - (C-A) = 180°-30°-45°
or, A+B+C-B+A-C+A = 105°
or, 3A = 105°
or, A = 35°
or, B = (35°+30°) = 65°
or, C = (35°+45°) = 80°
so, A = 35°.
B = 65°.
C = 80°.
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