Question

angles if a quardilateral are (4x)°,5(x+2)°,(7x-20)° and6(x+3)° .find x

Answer 1

sum of angles of a quadrilateral is 360 so,
4x+5(x+2)+(7x-20)+6(x+3)=360
4x+ 5x+10+ 7x-20+ 6x+18 =360
9x-10+13x+18=360
22x+8=360
22x=360-8
22x=352
x=353/22
this is the value of x or covert it in simples form