Angles of a hexagon are x+10,2x+20,2x-20,3x-50,x+40 and x-20. Find x
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Angles of a hexagon are x + 10°, 2x + 20°,
2x – 20°, 3x – 50°, x + 40° and x + 20°
∴ But sum of an angles of a hexagon = (x – 2) × 180°
= (6 – 2) × 180° = 4 × 180° = 720°
But sum = x + 10 +2x + 20°+ 2x – 20° + 3x
-50° + x + 40 + x + 20
= 10x + 90 – 70 = 10x + 20
∴ 10x + 20 = 720° ⇒ 10x = 720 – 20 = 700
⇒ x = 700°/10 = 70°
∴ 70°
2x – 20°, 3x – 50°, x + 40° and x + 20°
∴ But sum of an angles of a hexagon = (x – 2) × 180°
= (6 – 2) × 180° = 4 × 180° = 720°
But sum = x + 10 +2x + 20°+ 2x – 20° + 3x
-50° + x + 40 + x + 20
= 10x + 90 – 70 = 10x + 20
∴ 10x + 20 = 720° ⇒ 10x = 720 – 20 = 700
⇒ x = 700°/10 = 70°
∴ 70°
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