Question

Angles of a quadrilateral are (4x)°, 5(x+2)°, (7x-20)° and 6(x+3)°
Find:
(I) The value of X
(II) Each angle of the quadrilateral

Answer 1

HLO MATE ✋✋
Simran Here !!!!!

HERE IS UR ANSWER _____________
________________________________⭐⭐⭐

$Given \: that : \\ Angles \: of \: quad.are \: (4x)°, \: 5(x + 2)°, \: (7x - 20), \: 6(x + 3) \\ \\ \: We \: know \: that \: Sum \: of \: all \: angles \: of \: quad. = 360 \\ \\ Now ,\: Acc \: to \: statement : \\ \\ = > 4x + 5(x + 2) + 7x - 20 + 6(x + 3) = 360 \\ \\ = > 4x + 5x + 10 + 7x - 20 + 6x + 18 = 360 \\ \\ = > 22x + 8 = 360 \\ \\ = > 22x = 352 \\ \\ = > x = 16$

(I) The value of 'x' is 16 ✔
(II) Angles are : 64° , 90° , 92° , 114 °...✔
_______________________________⭐⭐
☺HOPE IT HELPS UH ☺
^_^

❤BE BRAINLY❤
And Keep Smiling ✌

Answer 2

Answer:

Angles of quad.are(4x)°,5(x+2)°,(7x−20),6(x+3)

Sum of all angles of quad.=360

Now,Acc to statement:

=>4x+5(x+2)+7x−20+6(x+3)=360

=>4x+5x+10+7x−20+6x+18=360

=>22x+8=360

=>22x=352

=>x=16