Angles of a triangle ABB are such that angle B is double of angle A and angle C is 20 degree . What are the measures of all the angles?
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Answered by
11
A = 160/3. B= 320/3
A+B+C=180
A+B+C=180
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Hi friend
When angels of a ∆ ABB are such that angle B is double of angle A and C is 20 °.
So that. ===. A==(160/3)
B======(320/3)
The measure of all the angels are A+B +C =180°
Hope it is helpful...
When angels of a ∆ ABB are such that angle B is double of angle A and C is 20 °.
So that. ===. A==(160/3)
B======(320/3)
The measure of all the angels are A+B +C =180°
Hope it is helpful...
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