Angles of a triangle are (x-40 o ), (x-20 o ), (1/2x-10 o ). Find the value of x
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x-40+x-20+1/2x-10= 180 ( all the angles of a triangle constitutes to 180 degree)
x+x+1/2x=180+40+20+10
5/2 x= 250
x=250×2/5
x=100
x+x+1/2x=180+40+20+10
5/2 x= 250
x=250×2/5
x=100
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