Angles of a triangle are x ,(x+ 10)
degree and 70 degree find the two angles of a triangle
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Answer:
1st angle = 50°
2nd angle = 60°
Step-by-step explanation:
let, 1st angle be x
and 2nd angle be (x+10)
So,
x+(x+10)+70°=180° (sum of all interior angle)
x+x+10+70°=180°
2x+80°=180°
2x=180°-80°
2x=100°
x=100°/2
x=50°
Now, 1st angle = 50°
2nd angle = 60°
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