angles of quardrilateral are 4x,5(x+2)°,(7x-20)° and 6(x+3)°.find: (a) the value of x (b) each angle of the quardrilateral
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Angles of the quadrilateral are 4x, 5(x+2)°,(7x-20)° and 6(x+3)°
(a) According to the angle sum property, the angles of a quadrilateral sum up to 360°.
Thus,
(4x) + [5(x+2)] + (7x-20) + [6(x+3)] = 360°
4x + 5x + 10 + 7x - 20 + 6x + 18 = 360°
22x + 8 = 360°
22x = 352°
x = 16°
(b) Hence the angles are,
- 4x° = 4(16°) = 64°
- 5(x+2)° = 5[(16°) + 2] = 90°
- (7x - 20)° = [7(16°) - 20] = 92°
- 6(x+3)° = 6[(16°)+3] = 114°
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