angles of the quadrilateral are (4x)°,5(x+2)°,(7x-20)°and6(x+3)° find the value of X
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As we know the sum of angles of quadrilateral is 360
Than
4x+5x+10+7x-20+6x+18=360
9x-10+13x+18=360
22x+8=360
22x=352
x=352/22
x=16
Then the angles are
First angle=16*4=64
Second angle =5x+10=80+10=90°
Third angle =(7*16)-20=112-20=92
Fourth angle =(6*16)+18=96+18=114
_________________________________
Verification
64+90+92+114=360
154+206=360
360=360
Hence proved
Than
4x+5x+10+7x-20+6x+18=360
9x-10+13x+18=360
22x+8=360
22x=352
x=352/22
x=16
Then the angles are
First angle=16*4=64
Second angle =5x+10=80+10=90°
Third angle =(7*16)-20=112-20=92
Fourth angle =(6*16)+18=96+18=114
_________________________________
Verification
64+90+92+114=360
154+206=360
360=360
Hence proved
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