Question

Angles opposite to equal sides of an isosceles triangle are equal.
PROVE IT
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Answer 1

here you go ☆☆

$\bold{abc \: be \:any \: triangle}$
$\bold{ad \: median}$
▪AD is perpendicular on BC

▪so in triangle ABD and ACD

▪AB=AC ( GIVEN )
▪< ADB= < ADC ( both 90° )
▪AD=AD ( common)

▪so by SAS , ABD =~ ACD

▪therefore by cpct
< ABD=<ACD

HENCE PROVED

hope it helps you......