Question

. Angles opposite to equal sides of an isosceles triangle are equal.
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Prove

Answer 1

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Jay hind..

Answer 2

Hey!
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Given : A triangle ABC with AB = AC [ Refer to Attachment ]

To prove : Angle B = Angle C

Construction : Draw AD perpendicular to BC.


Proof : Consider ∆ ADB and ∆ ADC,

AB = AC [ given ]


Angle 1 = Angle 2 [ 90° Each ]

AD = AD [ Common ]


✔Hence ∆ADB is congruent to ∆ ADC [ by ASA rule ]

◾ angle B = Angle C. [ By CPCT ]


✨Hence proved !!


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