Angles Q and R of a ∆ PQR are 25° and 65°. Write which of the following is true:
(i) PQ^2 + QR^2 = RP^2
(ii) PQ^2 + RP^2 = QR^2
(iii) RP^2 + QR^2 = PQ^2
Answers
Answered by
7
Answer:
explain question what you are saying
Answered by
28
Answer:
(ii) PQ^2 + RP^2 = QR^2
Option (ii) is true.
Step-by-step explanation:
The reason being that, it is given that <Q and <R are 25° and 65° respectively. Thus on adding them we get 90°. This clearly shows that third angle that is <P is 90°. So if we apply Pythagoras theorem in right triangle PQR, we get,
(QR)^2 = (PQ)^2 + (RP)^2
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