Question

Angles Q and R of a Triangle PQR are 25 degrees and 65 degrees. Write which of the following is true: (1). PQ² + QR² = RP² (2). PQ² + RP² = QR² (3). RP² + QR² = PQ².



Note:- pagal people not allow​

Answer 1

This is converse of Pythagoras theorem

We can prove this contradiction sum q

2

=p

2

+r

2

in ΔPQR while triangle is not a rightangle

Now consider another triangle ΔABC we construct ΔABC AB=qCB=b and C is a Right angle

By the Pythagorean theorem (AC)

2

=p

2

+r

2

But we know p

2

+r

2

=q

2

and q=PR

So (AB)

2

=p

2

+r

2

=(SR)

2

Since PQ and AB are length of sides we can take positive square roots

AC=PQ

All the these sides ΔABC are congruent to ΔPQR

So they are congruent by sss theorem.

Aap mannat Di ho kya!!!!??

Answer 2

Arey but yeh I'd aap pehle bhi use krte the kya........

Yahan tak mujhe yaad hai yeh I'd toh arash Ki hai aapke paas kaise aayi........xd