Question

angles Qand R of ∆PQR are 47° and 43°. write which of the following is true:
a)PQ²+QR² = RP²
B) PQ²+PR²=QR²
C)RP²+QR²=PQ²​

Answer 1

$\huge{\boxed{\rm{\red{PQ²+PR²=QR²}}}}$

Answer:

From the given triangle

angle Q =47°

angle R=43°

we know that the sum of three angles in a triangle is 180°

=>angle P + angle Q +angle R=180°

=>angle P+47°+43°=180°

=>angle P+90°=180°

=>angle P=180°-90°

=>angle P=90°

Here angle P =90°

so given triangle is a right angled triangle.

Hypotenuse =QR

By Pythagoras theorem

QR²=PQ²+PR² is true

Right angled triangle:-

One angle is 90° then the angle is called right angled triangle.

Pythagoras theorem:-

The square of hypotenuse is equal to the sum of the squres of the other two sides