Question

Angular deviation of red and violet color through prism is 6 and 9 respectively. The dispersive power of prism is 1 point 0.5 0.2 0.6 0.4​

Answer 1

Answer:

hope the image explains you with a mass explaination

Answer 2

Answer:

The dispersive power of the prism, ω, measured is $0.4$.

Therefore, option d) $0.4$ is the correct option.

Explanation:

Given,

The angular deviation of red color, $\delta_{r}$ = $6\textdegree$

The angular deviation of violet color, $\delta_{v}$ = $9\textdegree$

The prism's dispersive power, $\omega$ =?

As we know,

• The dispersive power is defined as the ratio of the angular dispersion of the two wavelengths to the deviation of the mean wavelength.
• $\omega = \frac{\theta}{\delta}$      -------equation (1)

Here,

• $\omega$ = The dispersive power
• $\theta$ = The angular dispersion
• $\delta$ = The deviation of mean

Now, we have to calculate the angular dispersion (θ) by using the equation given below:

• $\theta = \delta_{v} - \delta_{r}$

After putting the given values in the equation, we get:

• $\theta = 9\textdegree - 6\textdegree$
• $\theta = 3 \textdegree$

Now, we have to calculate the deviation of the mean wavelength by using the equation given below:

• $\delta =\frac{ \delta_{v} + \delta_{r} }{2}$
• $\delta =\frac{ 9\textdegree + 6\textdegree }{2}$
• $\delta = 7.5\textdegree$

Now, after putting the values of θ and δ in the equation (1), we get:

• $\omega = \frac{3\textdegree}{7.5\textdegree}$
• $\omega = 0.4$

Hence the dispersive power, $\omega = 0.4$