Angular momentum of a planet of mass m moving around sun
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Answer:
Angular momentum of a planet of mass m moving around sun
Correct option (3)
L/2m
Explanation:
dA/dt = L/2m
Answered by
1
Angular momentum
=
L
=L
Mass of the Planet
=
m
.
=m.
Relation between Angular momentum, mass of the planet and Areal Velocity of the Planet is given by the formula
L
=
2
m
×
Δ
A
/
Δ
t
L=2m×ΔA/Δt
Proof of this formula,
L
=
m
v
r
L=mvr
Multiplying and dividing the R.H.S. by 2.
∴
L
=
2
m
v
r
/
2
∴L=2mvr/2
∴
L
=
2
m
×
v
×
r
/
2
∴L=2m×v×r/2
∴
L
=
2
m
×
d
r
/
d
t
×
r
/
2
∴L=2m×dr/dt×r/2
∴
L
=
2
m
×
d
A
/
d
t
∴L=2m×dA/dt
∴
L
=
2
m
Δ
A
/
Δ
t
∴L=2mΔA/Δt
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