Question

Angular momentum of an electron in fourth orbit in bohr's hydrogen atom

Answer 1

use the formula
$\frac{nh}{2\pi}$
where h is 6.6×10-³⁴

Answer 2

Answer:

Angular momentum of an electron in the fourth orbit in Bohr's hydrogen atom is $2\frac{h}{\pi }$

Explanation:

• The angular momentum $(L)$  gives the quantity of rotation in a rotating body

• From Bohr's postulate for allowed orbits, angular momentum is given by the formula

         $L=n\frac{h}{2\pi }$

         where,

         $n$- the principal quantum number

         $h=6.62*10^{-34}$(Planck's constant)

for the fourth orbit of the hydrogen atom

the principal quantum number $n=4$

⇒

the angular momentum is $L=4*\frac{h}{2\pi } =2\frac{h}{\pi }$