Question

Angular momentum of an orbit of a H like
species in which the electron revolving
is 4.2197x10-34 JS . The number of waves
made by the electron in that orbit​

Answer 1

Answer:

angular momentum = mvr = nh / 2pi

angular momentum = 4.2197 x 10^-34 Js

thus angular momentum = nh/ 2pi

h = planks constant = 6.626 x 10^-34 Js

n =?

4.2197 x 10^-34 = n x .626 x 10^-34 / 2 x pi

n = (4.2197 x 10^-34 x 2 x 22 ) / 7 x 6.626 x 10^-34

n = (0.636 x 2 x 22 x 10^(-34 +34) / 7

n = 3.99

which is approximately 4

thus n = 4

Explanation:

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Answer 2

The number of waves made by the electron in that orbit​ is 4.

Given: The angular momentum of an orbit of an H-like species is 4.2197 x 10^-34 J.s.

To Find: The number of waves made by the electron in that orbit​

Solution:

• We know that the formula for the angular momentum of an H-like species is given by,

        mvr = nh / 2π                              .... (1)

where, m = mass of the species, v = velocity of the species, r = radius of the species, n = orbit number, h = Planck's constant

• Whenever the number of waves made by the electron is asked, it means, we need to find the orbit number (n).

Coming to the numerical, we are given,

    Angular momentum = 4.2197 x 10^-34 J.s , h = 6.626 × 10^-34 J.s

  From (1), we have;

    mvr = nh / 2π = 4.2197 x 10^-34

⇒  nh / 2π = 4.2197 x 10^-34

⇒ n = ( 4.2197 x 10^-34 × 2 × π ) / ( 6.626 × 10^-34 )

⇒ n = 26.499 / 6.626

      = 3.999  

      ≅ 4

Hence, the number of waves made by the electron in that orbit​ is 4.

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