Angular momentum of body changes by 100 kgm^2 When its angular velocity changes from 50 rad/s to 25 rad/s Then Moment of Inertia of the body about the axis of rotation is
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Answer:
Explanation:
∆L= I × ∆angular velocity
Here,
∆L= 100 kg/m^2
∆ angular velocity= 50-25
=25 rad/s
Putting in the formula, we get
100= I × 25
I = 4 kg m^2
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