Question

Angular position of a particle moving on a circular path varies according to the equation e = t^4 - 3t^3 + 4t^2 - 2t (where theta is in radian and t is in seconds). Find angular acceleration at timet = lsec.​

Answer 1

Answer:

Angular displacement, θ=2t3+0.5

Angular velocity, ω=dtdθ

⟹θ=6t2

At t=2 seconds

ωt=2=6×4=24 rad/s

Answer 2

Answer:

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