Angular speed of the motor increased from 1200 rpm to 3120 rpm in 16 seconds what is the angular acceleration and how many revolutions does motor makes during in this time
Answers
Answered by
4
HELLO ,
initial angular velocity, w1 = 1200 rpm = 1200*2pi/60 = 40 pi rad/s
Final angular velocity, w2 = 3120 rpm = 3120*2pi / 60 = 104 pi rad/s
Time t = 16 s
(i)Angular acceleration, a = (104-40)/16 = 64pi/16 = 4 pi rad/s^2
(ii) Angle, theta = 40pi*16 + ½*4pi * 256 = 1152pi rad
Thus, number of revolutions, n= 1152pi/2pi revolutions
= 576 rev
HOPE IT HELPS
initial angular velocity, w1 = 1200 rpm = 1200*2pi/60 = 40 pi rad/s
Final angular velocity, w2 = 3120 rpm = 3120*2pi / 60 = 104 pi rad/s
Time t = 16 s
(i)Angular acceleration, a = (104-40)/16 = 64pi/16 = 4 pi rad/s^2
(ii) Angle, theta = 40pi*16 + ½*4pi * 256 = 1152pi rad
Thus, number of revolutions, n= 1152pi/2pi revolutions
= 576 rev
HOPE IT HELPS
Similar questions