Angular velocity of the orbit n=4
Answers
Velocity of an electron in He
Velocity of an electron in He +
Velocity of an electron in He + ion in an orbit=
Velocity of an electron in He + ion in an orbit= nh
Velocity of an electron in He + ion in an orbit= nh2πZe
Velocity of an electron in He + ion in an orbit= nh2πZe 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =u
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He +
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit=
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Z
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h 2
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h 2 =r
Velocity of an electron in He + ion in an orbit= nh2πZe 2 =uRadius of He + ion in an orbit= 4π 2 me 2 Zn 2 h 2 =rAngular velocity (w)=
)= r
)= ru
)= ru
)= ru =
)= ru = n
)= ru = n 3
)= ru = n 3 h
)= ru = n 3 h 3
)= ru = n 3 h 3
)= ru = n 3 h 3 8π
)= ru = n 3 h 3 8π 3
)= ru = n 3 h 3 8π 3 Z
)= ru = n 3 h 3 8π 3 Z 2
)= ru = n 3 h 3 8π 3 Z 2 me
)= ru = n 3 h 3 8π 3 Z 2 me 4
)= ru = n 3 h 3 8π 3 Z 2 me 4
)= ru = n 3 h 3 8π 3 Z 2 me 4
)= ru = n 3 h 3 8π 3 Z 2 me 4
)= ru = n 3 h 3 8π 3 Z 2 me 4 =
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2)
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 )
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7)
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2)
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 )
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4 =2.067×10
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4 =2.067×10 16
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4 =2.067×10 16 sec
)= ru = n 3 h 3 8π 3 Z 2 me 4 = (2) 3 ×(6.626×10 −27 ) 3 8×(22/7) 3 ×(2) 2 ××(9.108×10 −28 )×(4.803×10 −10 ) 4 =2.067×10 16 sec −1