Question

Anil,abhay and sanjay can complete a piece of work in 10 days 12 days and 15 days respectively. All of them started working together but anil left after working for 2 days and abhay left 3 days before the completion of work. How long did the work lasts

Answer 1

for 15days the work lasts

Answer 2

Answer:

Work last for 8 days

Step-by-step explanation:

Given:

Number of days taken by Anil to complete the work = 10

Work done by Anil in a day = 1/10

Number of days taken by Abhay to complete the work = 12

Work done by Abhay in a day = 1/12

Number of days taken by Sanjay to complete the work = 15

Work done by Sanjay in a day = 1/15

All worked for three,

So, Work finished in 3 days = $3\times(\frac{1}{10}+\frac{1}{12}+\frac{1}{15})=\frac{3}{4}$

For last three days only Sanjay worked.

work in 3 days by Sanjay = 3/15=1/5

In middle work is done by Sanjay and Abhay.

Work done by Sanjay and Abhay in a day = 1/12+1/15=3/20

Work left to do in middle =$1-(\frac{3}{4}+\frac{1}{5})=1-\frac{19}{20}=\frac{1}{20}$

So, Number of days taken by Sanjay and Abhay to do work = $\frac{3}{20}\div\frac{1}{20}=\frac{3}{20}\times\frac{20}{1}=3$

Number of days = 2 + 3 + 3 = 8

Therefore, Work last for 8 days