Math, asked by kumaraman6989, 1 year ago

anil and raju can work together to finish a work in 10 days. they together work on it for 2 days and then raju leaves. the rest of the work was done by anil alone in 30 days. in how much time can raju do the work alone?

Answers

Answered by sonal2357
2
38 days


Hope it is right
Answered by bhagyashreechowdhury
6

Given:

Anil and Raju can finish the work together in 10 days

They work together for 2 days

Raju leaves after 2 days and Anil does the rest of the work alone in 30 days

To find:

The time in which Raju can do the work alone

Solution:

In 1 day, the amount of work done by Anil and Raju together = \frac{1}{10}

Anil and Raju have worked together for 2 days

∴ In 2 days, the amount of work done By Anil and Raju together = \frac{2}{10} = \frac{1}{5}

∴ Remaining work to be done = 1 - \frac{1}{5}  = \frac{5 - 1}{5} = \frac{4}{5}amount of work done by Anil alone in 30 days

So,

If \frac{4}{5}th of the work is done in 30 days

Then, the complete work will be done by Anil in = 30 * \frac{5}{4} = \frac{150}{4} = \frac{75}{2} days

Now,

The amount of work by Raju alone in 1 day is,

= [Amount of work done by Raju and Anil in 1 day] - [Amount of work done by Anil in 1 day]

= \frac{1}{10}\: -\: \frac{2}{75}\\  \\\\= \frac{15\: -\: 4}{150}\\\\\\= \frac{11}{150}

Thus, Raju can do the work alone in \frac{150}{11} \:days \:or\:13.63\:days.

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