Math, asked by zaidibijnorialiabbas, 10 months ago

Anil borrowed a certain sum from sunil for 2 years at simple interest.Anil lent this sum to mohit at the same rate for 2 years at compound interest .At the end of 2 years.Anil received ₹110 as compound interest but paid ₹ 100 as simple interest.Find the sum and rate of interest​

Answers

Answered by kams1171
40

Answer:

Step-by-step explanation:

For first year, SI and CI will be same

SI for 2 years = ₹ 100

SI for 1st year = ₹ 50

CI for 1st year = ₹ 50

CI for 2 years = ₹ 110

CI for 2nd year = ₹ 110 - ₹50 = ₹60

It means SI on ₹50 on R% for one year is ₹10

10=50×R×1 /100

R= 10×100 /50 = 20%

Now

SI =PRT/100

100 = P×20×2 /100

P= 100×100 /20×2 = 10000/40 = ₹250

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