Math, asked by aditsharma0410, 1 month ago

Anil borrowed rupees 18000 from Rakesh at 8% per annum simple interest for 2 years if Anil had borrowed the sum at 8% per annum compound interest for extra amount food he has to pay???????

please tell correct answer​

Answers

Answered by vaishpthk1602
1

Answer:

Given

Money borrowed (P) = Rs 18000

Rate (R) = 8% p.a.

Time (n) = 2 years

Simple Interest = PRT / 100

= Rs (18000 × 8 × 2) / 100

= Rs 2880

In case of compound interest

A = P {1 + (R / 100)}n

= Rs 18000 {1 + (8 / 100)}2

= Rs 18000 × (27 / 25)2

= Rs 18000 × (27 / 25) × (27 / 25)

We get,

= Rs 104976 / 5

= Rs 20995.20

Hence,

Compound interest = Amount – Principal

= Rs 20995.20 – Rs 18000

= Rs 2995.20

Now,

Difference between compound interest and simple interest

= Rs 2995.20 – Rs 2880

= Rs 115.20

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