Question

Anil bought a second hand scooter for ₹7500 and spent ₹500 on its repairs. Then he
sold it to Deepak at a loss of 12%. What is Anil’s loss ?

Answer 1

Answer:

Hope this may help you.

Answer 2

To Find :

The loss recured by Anil.

Given :

• Cost Price = ₹ 7500

• Cost on repairing = ₹ 500

• Loss Percentage = 12 %

We know :

⠀⠀⠀⠀⠀⠀Formula for Loss Percentage :

$\underline{\boxed{\bf{L\% = \bigg(\dfrac{L}{CP} \times 100\bigg)\%}}}$

Where :-

• L% = Loss Percentage
• L = Loss Recured
• CP = Cost Price

Concept :

According to the Question , the cost price of thr car will be the sum of original cost Price and the cost on repairing it. i.e,

$\boxed{\begin{minipage}{7 cm} \bf{Total\:cost\:Price\::} \\ \\ :\implies \bf{CP\:of\:Scooter + Cost\:on\:repairing} \\ \\ :\implies \bf{7500 + 500} \\ \\ :\implies \bf{8000} \\ \\ \therefore \bf{Total\:Cost\:Price = 8000} \end{minipage}}$

Hence, the cost Price of the scooter is ₹ 8000.

Hence, now putting the value in the equation , we can find the required value.

Solution :

Using the formula and substituting the values in it , we get :-

$:\implies \bf{L\% = \bigg(\dfrac{L}{CP} \times 100\bigg)\%}$

$:\implies \bf{12\% = \bigg(\dfrac{L}{8000} \times 100\bigg)\%}$

$:\implies \bf{12 \not{\%} = \bigg(\dfrac{L}{8000} \times 100\bigg)\not{\%}}$

$:\implies \bf{12 = \bigg(\dfrac{L}{8000} \times 100\bigg)}$

$:\implies \bf{12 = \dfrac{L}{80}}$

$:\implies \bf{12 \times 80 = L}$

$:\implies \bf{960 = L}$

$\therefore \bf{Loss = 960}$

Hence, the loss recured by Anil is Rs. 960.