Anil bought a second hand Scooter for rupees 7500 and sold it to Deepak at a loss of 12% how much did Deepak pay step by step explanation of this question only
Answers
Answer:
Step-by-step explanation:
Anil spent=7500+500=8000rs.
now,12%of 8000 is=8000×12÷100
=960rs
so,anil lost=8000-960
=7040rs.
Given:
✰ C.P of a scooter = ₹7500
✰ Percentage of loss accrued = 12%
To find:
✠ How much did Deepak pay?
Solution:
Let's understand the concept! Anil bought a second hand Scooter for ₹7500, that means the cost price of a scooter is equal to ₹7500 and we have loss percentage. Now, we need to find how much did Deepak pay that means the selling price of the scooter that Anil gave to Deepak is equal to the amount of money Deepak paid to Anil. So, we will find the selling price by using formula.
➛ C.P of a scooter = ₹7500
➛ Percentage of loss accrued = 12%
✭ S.P = (100 - loss%)/100 × C.P ✭
➛ S.P = (100 - 12)/100 × 7500
➛ S.P = 88/100 × 7500
➛ S.P = 88/1 × 75
➛ S.P = 88 × 75
➛ S.P = ₹6600
∴ The amount of money Deepak pay = ₹6,600
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