Math, asked by manjeetjamwal10393, 4 months ago

Anil can do a piece of work in 16 days which Shashi
can finish in 24 days. If they work on alternate days with
Anil starting, in how many days the work will be finished?​

Answers

Answered by prasanthikuchipudi
0

Answer:

19 days

Step-by-step explanation:

Anil can do a piece of work in 16 days which Shashi

can finish in 24 days.

LCM of 16,24 is 48p

Anil works for 48p/16=3p

Shashi works for 48p/24=2p

Anil and shashi works alternate days

Anil work 3p in 1 day

shashi work 2p in next day

total 5p=2 days

5p*9=2*9 days

 45p=18 days

remaining work 48-45=3p

3p=1 day done by anil

total days 18+1=19 days

Answered by RvChaudharY50
1

Given :-

  • Anil can do a piece of work in = 16 days.
  • Shashi can finish in = 24 days.
  • Anil starts the work and the work on alternate days.

To Find :-

  • In how many days the work will be finished ?

Solution :-

LCM of (16 and 24) = 48 units = Let total work .

so,

→ Efficiency of Anil = (Total work) / (Total days) = 48/16 = 3 unit/day .

→ Efficiency of Shashi = (Total work) / (Total days) = 48/24 = 2 unit/day .

then,

→ In first day, Anil completes work = 3 unit .

→ In second day, Shashi completes work = 2 unit .

therefore,

→ 5 units of work completes in = 2 days .

→ 45 units of work completes in = 2 * 9 = 18 days.

so ,

→ On 19th day , it turns of Anil now and he completes = 3 units .

→ In 19 days work completes = 45 + 3 = 48 units = Total work.

Hence, The work will finished in 19 days.

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