Anil deposited Rs 73,000 in a bank. If the currency notes given by him to the bank were in denomination Rs10, Rs50 and Rs 100 in the ratio 3:4:5 respectively, find the number of notes of each denomination Anil deposited.
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Answer:
300, 400 and 500
Step-by-step explanation:
Let the ratio 3:4:5 be 3x 4x and 5x
3x(10) + 4x(50) + 5x(100) = 73000
30x + 200x + 500x = 73000
730x = 73000
x = 73000/730
x = 100
Thus, no. of 10 rs notes = 3x = 3(100) = 300
no. of 50 rs notes = 4x = 4(100) = 400
no. of 100 rs notes = 5x = 5(100) = 500
Hence, the number of notes of each denomination was 300, 400 and 500 respectively.
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