Math, asked by sajalkhandelwal959, 11 months ago

Anil is 19 years younger than his cousin.After 5 years their ages will be in ratio 2:3.Find their present ages

Answers

Answered by ayushlakhera815
5

Answer:

Step-by-step explanation:

Let Anil age be X

And his cousin be X+19( given in question)

Ratio of their ages =2:3

Anil age/his cousin age = 2:3

X+5/X+24=2/3

By cross multiplying

3x+15=2x+48

3x-2x=48-15

X=33

Anil age is 33 years and his cousin is X+19=33+19=52 years

Answered by Anonymous
2

GIVEN:-

Anil is 19 years younger than his Cousin.

ratios of their ages after 5 years = 2:3

FIND:-

THEIR PRESENT AGES ?

SOLUTION:-

Let age of Cousin be x years

\therefore Age of Anil = x-19 years

After 5 years

Age of Cousin = x+5 years

Age of Anil = x - 19 + 5 = x - 14 years

ACCORDING TO QUESTION

 \frac{x - 14}{x + 5}  =  \frac{2}{3}

 = 3 \times ( x - 14) = 2( x+ 5)

 =  > 3x - 42 = 2x + 10

collect \: like \: terms

 =  > 3x - 2x = 10 + 42

x = 52

So, Present age of:

Cousin = x = 52 years

Anil = x -19 = 52 - 19 = 33 years

so, \: Cousin\: present \: age \underline{ \boxed{52 \: years}}

and \: Anil\: present \: age \underline{ \boxed{33 \: years}}

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