Math, asked by adnankundlik, 1 year ago


anil is older than his friend baiju by 3 yrs. anil's father is thrice as old as anil. baiju is twice as his sister chitra. the ages of chitra and Anil's father differ by 49 yrs. find the ages of anil and baiju

Answers

Answered by ssp0405
148
Let chitra's age be x years.
Baiju' s age will be 2x years
Anil's age will be 2x+3 years.
By given condition,
3(2x+3)- x = 49
6x+9-x=49
6x-x=49-9
5x=40
x=8
thus, baiju's age = 2x = 2×8=16 years
anil's age = 2x+3=2×8+3=19 years.

kareenah: where is anil's father's age?
ssp0405: Anil's father's age is not asked.
tsarita443: Solve it by linear eq in one variable
Answered by RenatoMattice
80

Answer: The age of Anil and Baiju is 19 yrs and 16 yrs respectively.

Step-by-step explanation:

Let the age of Baiju's sister Chitra be x

Let the age of Baiju be 2x

Let the age of Anil be 2x+3

Let the age of Anil's father be 3(2x+3)=6x+9.

According to question, the age of chitra and Anil's father differ by 49 years,

So, it becomes,

6x+9-x=49\\\\5x=49-9\\\\5x=40\\\\x=\frac{40}{5}=8\ years

Hence, the age of baiju is 2x=2\times 8=16\ yrs

The age of Anil is 2x+3=2\times 8+3=16+3=19\ yrs

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