Question

Anil sell one transistor for Rs 880 at a gain of 10% and another for Rs 960 at a loss of 4% find his overall gain or loss percent

Answer 1

Solution :

1 ) Selling price of first transistor

(s.p) = Rs 880

gain( g ) = 10%

Let the Cost price = c.p

c.p = ( s.p × 100)/( 100 + g )

= ( 880 × 100 )/( 100 + 10 )

= ( 880 × 100 )/110

c.p = Rs 800

2 ) Selling price of second transistor

= Rs 960

Loss ( L ) = 4%

Cost price = ( s.p × 100 )/( 100 - L )

= ( 960 × 100 )/( 100 - 4 )

= ( 960 × 100 )/96

C.P = Rs 1000

3 ) Total cost price of two transistors

= Rs 800 + Rs 1000

= Rs 1800

4 ) Total selling price of two transistors

= Rs 880 + Rs 960

= Rs 1840

5 ) Total s.p > Total c.p

Therefore , Anil gets profit .

gain = Total s.p - total c.p

= Rs 1840 - Rs 1800

= Rs 40

6 ) Gain % = ( gain × 100 )/( total c.p )

= ( 40 × 100 )/1800

= ( 20/9 )%

≈ 2.22%

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