Anil sold 2 washing machines at 12000 each. On one he gains 25% and the other he loses 25%. How much does he gain or loss in the while transaction and find the overall gain or loss %
Answers
Answered by
24
S. P. Of 1st washing machine = ₹12000
Gain = 25%
C. P. Of 1st washing machine,
= S. P. x 100 / 100 + gain%
= 12000 x 100 / 100 +25%
= 12000 x 100 / 125
= ₹9600
Now, S. P. Of 2nd washing machine = ₹12000
Loss = 25 %
C. P. Of washing machine,
= S. P. x 100 / 100+ loss%
= 12000 x 100 / 100 - 25 %
= 12000 x 100 / 75
= ₹16000
Now, Total S. P. Of washing machines = S. P. Of 1st washing machine + S. P. Of 2nd washing machine = ₹12000 + ₹12000
= ₹24000
Now, Total C. P. Of washing machines = C. P. Of 1st washing machine + S. P. Of 2nd washing machine = ₹9600 + ₹ 16000
= ₹25600
Here, C. P. > S. P.
Therefore, loss = C. P. - S. P.
= ₹25600 - 24000
= ₹1600
Now, loss%= (loss / C. P.) x 100
= (1600 / 25600) x 100
= 6.25%
Gain = 25%
C. P. Of 1st washing machine,
= S. P. x 100 / 100 + gain%
= 12000 x 100 / 100 +25%
= 12000 x 100 / 125
= ₹9600
Now, S. P. Of 2nd washing machine = ₹12000
Loss = 25 %
C. P. Of washing machine,
= S. P. x 100 / 100+ loss%
= 12000 x 100 / 100 - 25 %
= 12000 x 100 / 75
= ₹16000
Now, Total S. P. Of washing machines = S. P. Of 1st washing machine + S. P. Of 2nd washing machine = ₹12000 + ₹12000
= ₹24000
Now, Total C. P. Of washing machines = C. P. Of 1st washing machine + S. P. Of 2nd washing machine = ₹9600 + ₹ 16000
= ₹25600
Here, C. P. > S. P.
Therefore, loss = C. P. - S. P.
= ₹25600 - 24000
= ₹1600
Now, loss%= (loss / C. P.) x 100
= (1600 / 25600) x 100
= 6.25%
Answered by
7
Question
Anil sold two washing machine at 12000 each.on one he a profit of 25% and another a loss of 25% .find his overall loss or profit in the whole transaction and find the overall gain or loss %
Solution
For 1st machine,
Hence the profit on 1st machine = ₹2400
For 2nd machine,
Hence loss on 2nd machine = ₹4000
Hence total loss/ profit = 4000 - 2400 = ₹1600
= (1600/25600) ×100
= 6.25%
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