Math, asked by errolamaheshkumar, 1 month ago

Anil went to supermarket with a total of ₹ 590. He carried the notes of denominations of ₹50, ₹20 and ₹10. It is noted that the ratio of number of ₹50 notes to ₹20 notes is 3:5. Totally he has 25 notes with him. With this observation, answer the following questions: 5M (i) What is the total currency he carried with him? (ii) How many ₹50 notes he has? (iii) How many ₹20 notes he has? (iv) How many ₹10 notes he has? (v) How many notes he has in total? answer it correctttttt​

Answers

Answered by Anonymous
0

Answer:

Check the Explanation

Step-by-Step Explanation:

Given Anil has 590 Rupees

Rs 50, 20 & 10 are there ⇒ Total 25 notes

Rs 50 & Rs 20 ⇒3:5

Notes of Rs 50 = 3x

Notes of Rs 20 = 5x

Notes of Rs 10 = 25− (3x+5x) = 25−8x.

Amount in 50 Rupee notes ⇒ 50 × 3x = 150x

Amount in 20 Rupee notes ⇒ 20 × 5x = 100x.

Amount in 10 Rupee notes ⇒10(25−8x) = 250 − 80x

Total Amount = 590 Rs

⇒150x+100x+250−80x=590

⇒250−80x=590−250

⇒170x=340

∴x=2

So Anil has,

Notes of Rs.50 = 3 x 2 = 6 i.e. 150 x 2 = 300Rs.

Notes of Rs.20 = 5 x 2 = 10 i.e. 100x 2 = 200Rs.

Notes of Rs.10 = 25−8 x 2 = 9 i.e. = 90Rs

Hope it helps!

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